When a system is taken from state A to state B along path ACB as shown in figure below, 80 J of heat flows into the system and the system does 30 J of work.
(i) How much heat flows into the system along path ADB if the work done by the system is 10 J :
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
(i) Since Δ E = q + w = 80 – 30 = 50
So for ADB
Δ E = q + w ; 50 = q – 10 ; q = 60 J
(ii) For B to A, Δ E = – 50 J
w = + 20 J
q = – 50 – 20 = – 70
heat is liberate.
(iii) In ADB process, DB process is isochoric, so w DB = 0
So , Δ E AD = q AD + w AD
–40 = q AD + (–10) ; q AD = –30 J
Now q AB = q AD + q DB ; 60 = – 30 + q DB
q DB = 90 J
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